Optimal. Leaf size=590 \[ \frac {11 \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^{13/2} \text {ArcTan}\left (\frac {\sqrt {b} \sqrt {e \sin (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt {e}}\right )}{8 b^{13/2} \sqrt [4]{-a^2+b^2} d}-\frac {11 \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^{13/2} \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {e \sin (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt {e}}\right )}{8 b^{13/2} \sqrt [4]{-a^2+b^2} d}-\frac {11 a \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^7 \Pi \left (\frac {2 b}{b-\sqrt {-a^2+b^2}};\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {\sin (c+d x)}}{8 b^7 \left (b-\sqrt {-a^2+b^2}\right ) d \sqrt {e \sin (c+d x)}}-\frac {11 a \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^7 \Pi \left (\frac {2 b}{b+\sqrt {-a^2+b^2}};\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {\sin (c+d x)}}{8 b^7 \left (b+\sqrt {-a^2+b^2}\right ) d \sqrt {e \sin (c+d x)}}+\frac {11 a \left (45 a^2-37 b^2\right ) e^6 E\left (\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{20 b^6 d \sqrt {\sin (c+d x)}}-\frac {11 e^5 \left (5 \left (9 a^2-2 b^2\right )-27 a b \cos (c+d x)\right ) (e \sin (c+d x))^{3/2}}{60 b^5 d}+\frac {11 e^3 (9 a+2 b \cos (c+d x)) (e \sin (c+d x))^{7/2}}{28 b^3 d (a+b \cos (c+d x))}+\frac {e (e \sin (c+d x))^{11/2}}{2 b d (a+b \cos (c+d x))^2} \]
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Rubi [A]
time = 0.93, antiderivative size = 590, normalized size of antiderivative = 1.00, number
of steps used = 15, number of rules used = 13, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.520, Rules
used = {2772, 2942, 2944, 2946, 2721, 2719, 2780, 2886, 2884, 335, 304, 211, 214}
\begin {gather*} \frac {11 a e^6 \left (45 a^2-37 b^2\right ) E\left (\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{20 b^6 d \sqrt {\sin (c+d x)}}-\frac {11 e^5 (e \sin (c+d x))^{3/2} \left (5 \left (9 a^2-2 b^2\right )-27 a b \cos (c+d x)\right )}{60 b^5 d}+\frac {11 e^{13/2} \left (9 a^4-11 a^2 b^2+2 b^4\right ) \text {ArcTan}\left (\frac {\sqrt {b} \sqrt {e \sin (c+d x)}}{\sqrt {e} \sqrt [4]{b^2-a^2}}\right )}{8 b^{13/2} d \sqrt [4]{b^2-a^2}}-\frac {11 e^{13/2} \left (9 a^4-11 a^2 b^2+2 b^4\right ) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {e \sin (c+d x)}}{\sqrt {e} \sqrt [4]{b^2-a^2}}\right )}{8 b^{13/2} d \sqrt [4]{b^2-a^2}}-\frac {11 a e^7 \left (9 a^4-11 a^2 b^2+2 b^4\right ) \sqrt {\sin (c+d x)} \Pi \left (\frac {2 b}{b-\sqrt {b^2-a^2}};\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right )}{8 b^7 d \left (b-\sqrt {b^2-a^2}\right ) \sqrt {e \sin (c+d x)}}-\frac {11 a e^7 \left (9 a^4-11 a^2 b^2+2 b^4\right ) \sqrt {\sin (c+d x)} \Pi \left (\frac {2 b}{b+\sqrt {b^2-a^2}};\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right )}{8 b^7 d \left (\sqrt {b^2-a^2}+b\right ) \sqrt {e \sin (c+d x)}}+\frac {11 e^3 (e \sin (c+d x))^{7/2} (9 a+2 b \cos (c+d x))}{28 b^3 d (a+b \cos (c+d x))}+\frac {e (e \sin (c+d x))^{11/2}}{2 b d (a+b \cos (c+d x))^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 211
Rule 214
Rule 304
Rule 335
Rule 2719
Rule 2721
Rule 2772
Rule 2780
Rule 2884
Rule 2886
Rule 2942
Rule 2944
Rule 2946
Rubi steps
\begin {align*} \int \frac {(e \sin (c+d x))^{13/2}}{(a+b \cos (c+d x))^3} \, dx &=\frac {e (e \sin (c+d x))^{11/2}}{2 b d (a+b \cos (c+d x))^2}-\frac {\left (11 e^2\right ) \int \frac {\cos (c+d x) (e \sin (c+d x))^{9/2}}{(a+b \cos (c+d x))^2} \, dx}{4 b}\\ &=\frac {11 e^3 (9 a+2 b \cos (c+d x)) (e \sin (c+d x))^{7/2}}{28 b^3 d (a+b \cos (c+d x))}+\frac {e (e \sin (c+d x))^{11/2}}{2 b d (a+b \cos (c+d x))^2}+\frac {\left (11 e^4\right ) \int \frac {\left (-b-\frac {9}{2} a \cos (c+d x)\right ) (e \sin (c+d x))^{5/2}}{a+b \cos (c+d x)} \, dx}{4 b^3}\\ &=-\frac {11 e^5 \left (5 \left (9 a^2-2 b^2\right )-27 a b \cos (c+d x)\right ) (e \sin (c+d x))^{3/2}}{60 b^5 d}+\frac {11 e^3 (9 a+2 b \cos (c+d x)) (e \sin (c+d x))^{7/2}}{28 b^3 d (a+b \cos (c+d x))}+\frac {e (e \sin (c+d x))^{11/2}}{2 b d (a+b \cos (c+d x))^2}+\frac {\left (11 e^6\right ) \int \frac {\left (\frac {1}{2} b \left (9 a^2-5 b^2\right )+\frac {1}{4} a \left (45 a^2-37 b^2\right ) \cos (c+d x)\right ) \sqrt {e \sin (c+d x)}}{a+b \cos (c+d x)} \, dx}{10 b^5}\\ &=-\frac {11 e^5 \left (5 \left (9 a^2-2 b^2\right )-27 a b \cos (c+d x)\right ) (e \sin (c+d x))^{3/2}}{60 b^5 d}+\frac {11 e^3 (9 a+2 b \cos (c+d x)) (e \sin (c+d x))^{7/2}}{28 b^3 d (a+b \cos (c+d x))}+\frac {e (e \sin (c+d x))^{11/2}}{2 b d (a+b \cos (c+d x))^2}+\frac {\left (11 a \left (45 a^2-37 b^2\right ) e^6\right ) \int \sqrt {e \sin (c+d x)} \, dx}{40 b^6}-\frac {\left (11 \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^6\right ) \int \frac {\sqrt {e \sin (c+d x)}}{a+b \cos (c+d x)} \, dx}{8 b^6}\\ &=-\frac {11 e^5 \left (5 \left (9 a^2-2 b^2\right )-27 a b \cos (c+d x)\right ) (e \sin (c+d x))^{3/2}}{60 b^5 d}+\frac {11 e^3 (9 a+2 b \cos (c+d x)) (e \sin (c+d x))^{7/2}}{28 b^3 d (a+b \cos (c+d x))}+\frac {e (e \sin (c+d x))^{11/2}}{2 b d (a+b \cos (c+d x))^2}+\frac {\left (11 a \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^7\right ) \int \frac {1}{\sqrt {e \sin (c+d x)} \left (\sqrt {-a^2+b^2}-b \sin (c+d x)\right )} \, dx}{16 b^7}-\frac {\left (11 a \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^7\right ) \int \frac {1}{\sqrt {e \sin (c+d x)} \left (\sqrt {-a^2+b^2}+b \sin (c+d x)\right )} \, dx}{16 b^7}+\frac {\left (11 \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^7\right ) \text {Subst}\left (\int \frac {\sqrt {x}}{\left (a^2-b^2\right ) e^2+b^2 x^2} \, dx,x,e \sin (c+d x)\right )}{8 b^5 d}+\frac {\left (11 a \left (45 a^2-37 b^2\right ) e^6 \sqrt {e \sin (c+d x)}\right ) \int \sqrt {\sin (c+d x)} \, dx}{40 b^6 \sqrt {\sin (c+d x)}}\\ &=\frac {11 a \left (45 a^2-37 b^2\right ) e^6 E\left (\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{20 b^6 d \sqrt {\sin (c+d x)}}-\frac {11 e^5 \left (5 \left (9 a^2-2 b^2\right )-27 a b \cos (c+d x)\right ) (e \sin (c+d x))^{3/2}}{60 b^5 d}+\frac {11 e^3 (9 a+2 b \cos (c+d x)) (e \sin (c+d x))^{7/2}}{28 b^3 d (a+b \cos (c+d x))}+\frac {e (e \sin (c+d x))^{11/2}}{2 b d (a+b \cos (c+d x))^2}+\frac {\left (11 \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^7\right ) \text {Subst}\left (\int \frac {x^2}{\left (a^2-b^2\right ) e^2+b^2 x^4} \, dx,x,\sqrt {e \sin (c+d x)}\right )}{4 b^5 d}+\frac {\left (11 a \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^7 \sqrt {\sin (c+d x)}\right ) \int \frac {1}{\sqrt {\sin (c+d x)} \left (\sqrt {-a^2+b^2}-b \sin (c+d x)\right )} \, dx}{16 b^7 \sqrt {e \sin (c+d x)}}-\frac {\left (11 a \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^7 \sqrt {\sin (c+d x)}\right ) \int \frac {1}{\sqrt {\sin (c+d x)} \left (\sqrt {-a^2+b^2}+b \sin (c+d x)\right )} \, dx}{16 b^7 \sqrt {e \sin (c+d x)}}\\ &=-\frac {11 a \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^7 \Pi \left (\frac {2 b}{b-\sqrt {-a^2+b^2}};\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {\sin (c+d x)}}{8 b^7 \left (b-\sqrt {-a^2+b^2}\right ) d \sqrt {e \sin (c+d x)}}-\frac {11 a \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^7 \Pi \left (\frac {2 b}{b+\sqrt {-a^2+b^2}};\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {\sin (c+d x)}}{8 b^7 \left (b+\sqrt {-a^2+b^2}\right ) d \sqrt {e \sin (c+d x)}}+\frac {11 a \left (45 a^2-37 b^2\right ) e^6 E\left (\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{20 b^6 d \sqrt {\sin (c+d x)}}-\frac {11 e^5 \left (5 \left (9 a^2-2 b^2\right )-27 a b \cos (c+d x)\right ) (e \sin (c+d x))^{3/2}}{60 b^5 d}+\frac {11 e^3 (9 a+2 b \cos (c+d x)) (e \sin (c+d x))^{7/2}}{28 b^3 d (a+b \cos (c+d x))}+\frac {e (e \sin (c+d x))^{11/2}}{2 b d (a+b \cos (c+d x))^2}-\frac {\left (11 \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^7\right ) \text {Subst}\left (\int \frac {1}{\sqrt {-a^2+b^2} e-b x^2} \, dx,x,\sqrt {e \sin (c+d x)}\right )}{8 b^6 d}+\frac {\left (11 \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^7\right ) \text {Subst}\left (\int \frac {1}{\sqrt {-a^2+b^2} e+b x^2} \, dx,x,\sqrt {e \sin (c+d x)}\right )}{8 b^6 d}\\ &=\frac {11 \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^{13/2} \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {e \sin (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt {e}}\right )}{8 b^{13/2} \sqrt [4]{-a^2+b^2} d}-\frac {11 \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^{13/2} \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {e \sin (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt {e}}\right )}{8 b^{13/2} \sqrt [4]{-a^2+b^2} d}-\frac {11 a \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^7 \Pi \left (\frac {2 b}{b-\sqrt {-a^2+b^2}};\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {\sin (c+d x)}}{8 b^7 \left (b-\sqrt {-a^2+b^2}\right ) d \sqrt {e \sin (c+d x)}}-\frac {11 a \left (9 a^4-11 a^2 b^2+2 b^4\right ) e^7 \Pi \left (\frac {2 b}{b+\sqrt {-a^2+b^2}};\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {\sin (c+d x)}}{8 b^7 \left (b+\sqrt {-a^2+b^2}\right ) d \sqrt {e \sin (c+d x)}}+\frac {11 a \left (45 a^2-37 b^2\right ) e^6 E\left (\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{20 b^6 d \sqrt {\sin (c+d x)}}-\frac {11 e^5 \left (5 \left (9 a^2-2 b^2\right )-27 a b \cos (c+d x)\right ) (e \sin (c+d x))^{3/2}}{60 b^5 d}+\frac {11 e^3 (9 a+2 b \cos (c+d x)) (e \sin (c+d x))^{7/2}}{28 b^3 d (a+b \cos (c+d x))}+\frac {e (e \sin (c+d x))^{11/2}}{2 b d (a+b \cos (c+d x))^2}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 6 vs. order 4 in
optimal.
time = 35.16, size = 930, normalized size = 1.58 \begin {gather*} \frac {11 (e \sin (c+d x))^{13/2} \left (\frac {\left (45 a^3-37 a b^2\right ) \cos ^2(c+d x) \left (3 \sqrt {2} a \left (a^2-b^2\right )^{3/4} \left (2 \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt {b} \sqrt {\sin (c+d x)}}{\sqrt [4]{a^2-b^2}}\right )-2 \text {ArcTan}\left (1+\frac {\sqrt {2} \sqrt {b} \sqrt {\sin (c+d x)}}{\sqrt [4]{a^2-b^2}}\right )-\log \left (\sqrt {a^2-b^2}-\sqrt {2} \sqrt {b} \sqrt [4]{a^2-b^2} \sqrt {\sin (c+d x)}+b \sin (c+d x)\right )+\log \left (\sqrt {a^2-b^2}+\sqrt {2} \sqrt {b} \sqrt [4]{a^2-b^2} \sqrt {\sin (c+d x)}+b \sin (c+d x)\right )\right )+8 b^{5/2} F_1\left (\frac {3}{4};-\frac {1}{2},1;\frac {7}{4};\sin ^2(c+d x),\frac {b^2 \sin ^2(c+d x)}{-a^2+b^2}\right ) \sin ^{\frac {3}{2}}(c+d x)\right ) \left (a+b \sqrt {1-\sin ^2(c+d x)}\right )}{12 b^{3/2} \left (-a^2+b^2\right ) (a+b \cos (c+d x)) \left (1-\sin ^2(c+d x)\right )}+\frac {2 \left (18 a^2 b-10 b^3\right ) \cos (c+d x) \left (\frac {\left (\frac {1}{8}+\frac {i}{8}\right ) \left (2 \text {ArcTan}\left (1-\frac {(1+i) \sqrt {b} \sqrt {\sin (c+d x)}}{\sqrt [4]{-a^2+b^2}}\right )-2 \text {ArcTan}\left (1+\frac {(1+i) \sqrt {b} \sqrt {\sin (c+d x)}}{\sqrt [4]{-a^2+b^2}}\right )-\log \left (\sqrt {-a^2+b^2}-(1+i) \sqrt {b} \sqrt [4]{-a^2+b^2} \sqrt {\sin (c+d x)}+i b \sin (c+d x)\right )+\log \left (\sqrt {-a^2+b^2}+(1+i) \sqrt {b} \sqrt [4]{-a^2+b^2} \sqrt {\sin (c+d x)}+i b \sin (c+d x)\right )\right )}{\sqrt {b} \sqrt [4]{-a^2+b^2}}+\frac {a F_1\left (\frac {3}{4};\frac {1}{2},1;\frac {7}{4};\sin ^2(c+d x),\frac {b^2 \sin ^2(c+d x)}{-a^2+b^2}\right ) \sin ^{\frac {3}{2}}(c+d x)}{3 \left (a^2-b^2\right )}\right ) \left (a+b \sqrt {1-\sin ^2(c+d x)}\right )}{(a+b \cos (c+d x)) \sqrt {1-\sin ^2(c+d x)}}\right )}{40 b^5 d \sin ^{\frac {13}{2}}(c+d x)}+\frac {\csc ^6(c+d x) (e \sin (c+d x))^{13/2} \left (\frac {\left (-168 a^2+65 b^2\right ) \sin (c+d x)}{42 b^5}-\frac {19 \left (a^3 \sin (c+d x)-a b^2 \sin (c+d x)\right )}{4 b^5 (a+b \cos (c+d x))}+\frac {a^4 \sin (c+d x)-2 a^2 b^2 \sin (c+d x)+b^4 \sin (c+d x)}{2 b^5 (a+b \cos (c+d x))^2}+\frac {3 a \sin (2 (c+d x))}{5 b^4}-\frac {\sin (3 (c+d x))}{14 b^3}\right )}{d} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(3820\) vs.
\(2(607)=1214\).
time = 0.76, size = 3821, normalized size = 6.48
method | result | size |
default | \(\text {Expression too large to display}\) | \(3821\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (e\,\sin \left (c+d\,x\right )\right )}^{13/2}}{{\left (a+b\,\cos \left (c+d\,x\right )\right )}^3} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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